Sig Fig Calculations

For each problem, calculate an answer, then round to the appropriate number of sig figs. For Multi-step questions, complete one part of the problem, round the answer, then continue the next portion and round the answer.

 

            Equation                                  calculated answer                 calculated answer, rounded

 

1)    4.5 + 2.34                                = 6.84                                      = 6.8

2)    4.5 Ð 5                                     =-.5                             = -1 or 0.

3)    6.00 + 3.411                            = 9.411                                    = ___9.41

4)    3.4 x 2.32                                = _7.888___                            = ___7.9____

5)    7.77 / 2.3                                 = 3.37826087                          = ___3.4__

6)    3.890 / 121                              = .0238842975_                      = .0239_

7)    1200 x 23.4                             = _28080                     = _28000 or 2.8 103___

8)    120 x 0.0002                           = __.024_                                = __.02_____

9)    78.5 + 0.0021 + 0.0099          = _78.512____                        = __78.5__

10) (3.4 x 8.90) x (2.3 + 9.002)     = __________                         = __________

                        (30.) x (11.3)               = 339                                       = 340

11) (2.31 x 103) / (3.1 x 102)          =7.45                                       = _7.4 or 7.5 __

12) 0.0023 + 65                             = __65.0023___                     = __65__

13) (3.4 x 106) + 210,349             = __________                         = __________

                        (360) + 210,349          = 210,709                    = 210,710 = 2.1071 x 105

14) (1.09 x 3.498) + 2.45001 Ð (2.123/0.0023)= __________     = __________

                        (3.80) + 2.45001 Ð ( 920)       =-913.74999     =-910 or Ð9.1 x 102

Express your answers to problems 7, 13 and 14 in scientific notation below.